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Nancy is making a kite based on the pattern below. About how much binding does Nancy need to cover the edges of the kite?

Nancy is making a kite based on the pattern below. About how much binding does Nancy-example-1
User Paul Houle
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1 Answer

1 vote

Check the picture below.

so the perimeter of the kite is x+x+y+y, namely 2x + 2y.



\bf \textit{using the pythagorean theorem} \\\\ c^2=a^2+b^2\implies c=√(a^2+b^2) \qquad \begin{cases} c=\stackrel{hypotenuse}{x}\\ a=\stackrel{adjacent}{8}\\ b=\stackrel{opposite}{15}\\ \end{cases} \\\\\\ x=√(8^2+15^2)\implies x=√(289)\implies \boxed{x=17} \\\\[-0.35em] ~\dotfill


\bf \begin{cases} c=\stackrel{hypotenuse}{y}\\ a=\stackrel{adjacent}{8}\\ b=\stackrel{opposite}{4}\\ \end{cases}\implies y=√(8^2+4^2)\implies y=√(80)\implies \boxed{y\approx 8.94} \\\\[-0.35em] ~\dotfill\\\\ 2x+2y\implies 2(17)+2(8.94)\implies 51.88\implies \stackrel{\textit{rounded up more}}{51.9}

Nancy is making a kite based on the pattern below. About how much binding does Nancy-example-1
User Najeem
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