Here we can use the concept of Height and distance
so here we know that
![Height = 1200 ft](https://img.qammunity.org/2020/formulas/physics/high-school/nfncsjb9afgu22oko7la45wdf27wzj2ohe.png)
angle of depression at the foot of the statue is 17 degree
angle of depression at the exit gate is 14 degree
So here the distance of foot of the statue is related as
![(h)/(d_1) = tan17](https://img.qammunity.org/2020/formulas/physics/high-school/52n2wbqccix40tntfnr3whoafqrwggh4bd.png)
so here we will have
![d_1 = (h)/(tan17)](https://img.qammunity.org/2020/formulas/physics/high-school/3kwwvc8uky76t9ioa5b4t5u9amlhn2q9rr.png)
![d_1 = (1200)/(tan17)](https://img.qammunity.org/2020/formulas/physics/high-school/b9es6if2n3smvq0jztsgp9ohablobvowdr.png)
![d_1 = 3925 ft](https://img.qammunity.org/2020/formulas/physics/high-school/yl61pymmo5ydl5xajj9bsg51ibhs5ugucw.png)
similarly for exit gate the distance is given as
![d_2 = (h)/(tan14)](https://img.qammunity.org/2020/formulas/physics/high-school/6kiire9pmigcf461ovfla7766pp66udd77.png)
![d_2 = (1200)/(tan14)](https://img.qammunity.org/2020/formulas/physics/high-school/qkdgqb09gcyxqz6244rvx9mng2b7zy2n56.png)
![d_2 = 4813 ft](https://img.qammunity.org/2020/formulas/physics/high-school/hg4pnzeu5fjvrq9b6polowlbwb85lh8fxg.png)
now the distance between gate and foot of statue is given as
![d_2 - d_1 = 4813 - 3925](https://img.qammunity.org/2020/formulas/physics/high-school/qj4fj0ubtikl2sutw4k1rf6n3kl1er35rf.png)
![d = 888 ft](https://img.qammunity.org/2020/formulas/physics/high-school/8gen50z5m3k5vvqiysxigorjt0xj4lqsba.png)