Answer:
Point-slope form of equation of a line that passes from (-1,3) and (0,0) is given as y-3=-3(x+1).
Slope-intercept form of equation is given as y=-3x.
Explanation:
In the question, it is given that the line passes from (-1,3) and (0,0).
It is asked to write the point-slope form of the equation and rewrite it as slope-intercept form.
Step 1 of 2
Passing point of line is (-1,3).
Hence,
and

Also, Passing point of line is (0,0).
Hence,
and

Substitute the above values to find the slope of line which is given by


Hence, slope of the line is -3
Step 2 of 3
It is obtained that m=-3

and

Substitute the above values in point-slope form of equation given by


Hence, point-slope form of equation given as y-3=-3(x+1).
Step 3 of 3
Solve y-3=-3(x+1) to write it as slope-intercept form given by y=mx+c

Hence, slope-intercept form of equation is given as y=-3x.