Question

PLEASE SHOW WORK OR EXPLAIN

Answer 1

cos(∠B) = CB/AB = ED/AD

Explanation:

`cosine=(adjacent)/(hypotenuse)\\\\adjacent=BC\\hypotenuse=AB\\\\\cos B=(BC)/(AB)\\\\\angle B\cong\angle D,\ \text{therefore}\ \cos B=\cos D.\\\\adjacent=ED\\hypotenuse=AD\\\\\cos B=\cos D=(ED)/(AD)`