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Kim solved the equation below by graphing a system of equations. log base 2 (3x-1) = log base 4 (x+8)

User Jfox
by
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2 Answers

3 votes

Answer:

The solution to the given equation is at point (1.353, 1.613). Explanation:

Given : Kim solved the equation below by graphing a system of equations.


\log_2(3x-1)=\log_4(x+8)

To find : What is the approximate solution to the equation?

Solution :

Let,
y_1=\log_2(3x-1)

and
y_2=\log_4(x+8)

Now, we plot these two equations.

The graph of
y_1=\log_2(3x-1) is shown with red line.

The graph of
y_2=\log_4(x+8) is shown with blue line.

The solution to this system will be their intersection point.

The intersection point of these graph is (1.353, 1.613)

Refer the attached graph below.

Therefore, The solution to the given equation is at point (1.353, 1.613).

Kim solved the equation below by graphing a system of equations. log base 2 (3x-1) = log-example-1
User Nishant Dixit
by
5.9k points
2 votes

Answer:

solution is


x=1.353,y=1.613

Explanation:

We are given equation as


log_2(3x-1)=log_4(x+8)

Firstly, we will find equations

First equation is


y=log_2(3x-1)

Second equation is


y=log_4(x+8)

now, we can draw graph

and then we can find intersection point

we can see that

intersection point is (1.353,1.613)

so, solution is


x=1.353,y=1.613

Kim solved the equation below by graphing a system of equations. log base 2 (3x-1) = log-example-1
User Ksumarine
by
4.8k points