Answer:
2
Explanation:
3^a = 25
3^b = 5
Take the log base 3 on both sides
log3(3^a) = log3(25)
a = log3(25)
Replace 25 with 5^2
a = log3(5^2)
The exponent goes out front log x^y = ylog x
a = 2 log3(5)
Now the second equation
Take the log base 3 on both sides
log3(3^b) = log3(5)
b = log3 (5)
Now divide a/b
a = 2 log3(5)
----------------
b = log3 (5)
The log3(5) cancels
a/b = 2