Answer:
Tunnel tent requires less nylon.
Explanation:
We are given two types of tents - pup tent and tunnel tent.
1. We will find the area of the pup tent.
As we see, the pup tent consists of 3 squares and 2 triangles.
A. Dimensions of the square is given by 8 ft by 8 ft.
So, the area of 3 squares = 3 × side²
i.e. Area of 3 squares =
= 3 × 64 = 192 ft².
B. The sides of the triangles are 8 feet.
As the triangles are all equilateral triangles.
The height is given by,
=
=
feet.
So, the area of the 2 triangles =
=
=
=
ft².
Thus, the area of the pup tent = 192 +
= 192 + 55.4 = 247.4 ft².
So, the area of the pup tent is 247.4 ft².
1. We will find the area of the tunnel tent.
As we see, the tunnel tent consists of 2 semi-circles,
cylindrical shape and a square base.
A. Diameter of the circle is 8 feet.
So, the radius of the circle is
= 4 feet.
Then, the area of the 2 semi-circles =
![2* (\pi r^(2))/(2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/80jj6lrfovv15frgldhi9jbjuxnw0180cg.png)
i.e. Area of the semi-circles =
![2* (\pi 4^(2))/(2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/5okdy52b4tjxxwczm5m2g78c2n24ybvxml.png)
i.e. Area of the semi-circles =
![2* (50.26)/(2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/ugbryxncp15f01j36pys3w2dhtzu5vei05.png)
i.e. Area of the semi-circles = 50.26 ft².
B. Dimensions of the cylinder is: Radius = 4 ft and Height = 8 ft.
As, we only have
cylindrical shape. We will divide the surface area by 2.
So, Lateral surface area of the
cylinder =
![\pi rh](https://img.qammunity.org/2020/formulas/mathematics/high-school/or1uj7n05wjvylcdkqlyzetbwm9mh2ph13.png)
i.e. Surface area of the cylinder =
![\pi 4* 8](https://img.qammunity.org/2020/formulas/mathematics/high-school/e4gtk6y45ojt6ez4e895dgttnxkamtzxmm.png)
i.e. Surface area of the cylinder =
![32\pi](https://img.qammunity.org/2020/formulas/mathematics/high-school/l11k2h385hn338oc5n2o4lvpuxodoq37be.png)
i.e. Surface area of the cylinder = 100.53 ft².
C. Dimensions of the square is given by 8 ft by 8 ft.
Then, the area of the base =
![side^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/yat5mw10ywjbqzvtn9c8bsxry4b2si1zlt.png)
i.e. Area of the square =
![8^(2)](https://img.qammunity.org/2020/formulas/mathematics/high-school/eb18dcoim01dpc8fp7iw4j6eij2d6ktay3.png)
i.e. Area of the square = 64 ft².
Thus, the area of the tunnel tent = 50.26 + 100.53 + 64 = 214.79 ft².
As, we have that,
247.4 ft² = Area of the pup tent > Area of the tunnel tent = 214.79 ft²
Hence, tunnel tent requires less nylon.