Question

PLEASE HELP

A boat is 20 ft away from a point perpendicular to the shoreline. A person stands at a point down the shoreline so that a 60° angle is formed between the closest point to the boat, the person, and the boat. How far is the person from the boat? Draw a picture showing the right triangle. Round your answer to the nearest tenth of a
foot. Show your work.

Answer 1

Explanation:

Since it is given that Distance between a boat that is away from a point perpendicular to the shore line = 20 feet

Angle of elevation that is formed between the closest point to the boat and the person = 60°

Now, we need to find the distance between the person and the boat.

Using the trigonometric ratios,

`sin60^{{\circ}}=(AB)/(AC)`

`(√(3))/(2)=(20)/(H)`

`(40)/(√(3))=H`

`H=(40)/(1.7)`

`H=23.0 feet`

Thus, the distance between the person and the boat is 23 feet.