Question

Please help! Fred mixes a solution using two types of solutions: 0.60 liters containing 10% alcohol and 0.40 liters containing 35% alcohol.

What is the alcohol concentration of the mixed solution?

Answer 1

Answer: 20%. Based on the given conditions, formulate:: 35% * 0.4 + 0.6 * 10% / 0.4 + 0.6Calculate the product

Answer 2

20%

Explanation:

Total Litres in mixture=(0.60+0.4)=1 Litre

alcohol in first portion:=0.10(0.60)=0.06 Litres

alcohol in second portion:=0.35(0.40)=0.14 Litres

Total alcohol in mixture = 0.06 +0.14 = 0.20

% of alcohol in mixture:

`(0.2)/(1) (100) = 20%`%