Write the equation of a line in slope -intercept form that is perpendicular to the given line and passes through the point 9,-32

Question

asked Apr 3, 2020 5.1k views

1 Answer

Ishan Bhatt · Answer 1 · 2020-04-09T09:59:24+0000

Answer:

y=-(7)/(2)x-(1)/(2)

Explanation:

The line Y=2/7x-1/7 in the comments has slope 2/7. A perpendicular line will have the negative reciprocal of 2/7. It's -7/2.

To write the equation, substitute -7/2 and the point (9,-32) into

y-y_1 = m(x-x_1)

$y--32=-(7)/(2)(x-9)\\\\y+32=-(7)/(2)x +(7*9)/(2)\\\\y+32=-(7)/(2)x+(63)/(2)\\\\y=-(7)/(2)x+(63-64)/(2)\\\\y=-(7)/(2)x-(1)/(2)$