Final answer:
The mass of 0.750 mole of aluminum oxide is 76.47 grams, calculated by multiplying the number of moles by the molar mass of Al2O3.
Step-by-step explanation:
To calculate the mass of 0.750 mole of aluminum oxide (Al2O3), you first need the molar mass of Al2O3. The molar mass is obtained by adding the masses of all the atoms in one mole of the substance. Aluminum has an atomic mass of 26.98 g/mol, and oxygen has an atomic mass of 16.00 g/mol. Therefore, the molar mass of Al2O3 is:
(2 × 26.98 g/mol) + (3 × 16.00 g/mol) = 53.96 g/mol + 48.00 g/mol = 101.96 g/mol
Once we know the molar mass, we can calculate the mass of 0.750 moles of Al2O3:
0.750 moles × 101.96 g/mol = 76.47 grams
Therefore, the mass of 0.750 mole of aluminum oxide is 76.47 grams.