Answer:
Option B is correct.
direct variation; k = 5/2
Explanation:
The Direct variation says:
![y \propto x](https://img.qammunity.org/2020/formulas/mathematics/high-school/iy5uxbgm9nve95at9gffh944ppe85ojp0j.png)
then the equation is of the form:
......[1] where k is the constant of variation.
From the given table:
Consider x = -2 and y = -5
Substitute these in [1] to solve for k;
![-5 = -2k](https://img.qammunity.org/2020/formulas/mathematics/middle-school/8gsa2l8hk9nozivrp1677busvq3hxwxqc7.png)
or
5 = 2k
Divide both sides by 2 we get;
![k = (5)/(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/vaauylbtwprli4sysspynu0y0aoe7d4d87.png)
⇒ the equation becomes:
![y = (5)/(2)x](https://img.qammunity.org/2020/formulas/mathematics/middle-school/kn5jqa3gf9fgwkmt7299ddtra67xokc9xd.png)
Check:
Take x = 4 and y = 10;
![y = (5)/(2)x](https://img.qammunity.org/2020/formulas/mathematics/middle-school/kn5jqa3gf9fgwkmt7299ddtra67xokc9xd.png)
![10 = (5)/(2) * 4](https://img.qammunity.org/2020/formulas/mathematics/middle-school/8dy5q00k8hwohrxmnaxaz36cup93z8c0l0.png)
![10 = 5 * 2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ozrova7fb2lm14vl581h5tea1syc3q0lfh.png)
10 = 10 True
Therefore, the direct variation ;
best describe the function represented by the table