Question

Estimate the magnitude of the electric field due to the proton in a hydrogen atom at a distance of

5.29×10 to the power of −11 m, the expected position of the electron in the atom.

Answer 1

Electric field due to a point charge is given as

`E = (kq)/(r^2)`

here we know that

`q = 1.6 * 10^(-19) C`

also the distance is given as

`r = 5.29 * 10^(-11) m`

now we will have

`E = ((9* 10^9)(1.6 * 10^(-19)))/((5.29 * 10^(-11))^2)`

so we will have

`E = 5.14 * 10^(11) N/C`

so above is the electric field due to proton