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Which shows a difference if squares 10y-4x^2 16y-x^2 8x^2-40x+25 64x^2-48x+9

2 Answers

3 votes

Answer:

On edge it's B. 16y^2-x^2

User Sjor
by
4.7k points
3 votes

Answer:

only option D is correct, i.e. 64x^2-48x+9 = (8x-3)².

Explanation:

Checking all given options:-

option A: 10y-4x^2

10y-4x^2 = 10y - (2x)²

option B: 16y-x^2

16y-x^2 = 16y - (x)²

option C: 8x^2-40x+25

8x^2-40x+25 = (2√2x)² -2*4x*5 + (5)²

Given option C does not make a perfect square.

option D: 64x^2-48x+9

64x^2-48x+9 = (8x)² -2*8x*3 + (3)²

Using the formula:- a² -2ab + b² = (a-b)²

Here a = 8x and b = 3.

So, 64x^2-48x+9 = (8x-3)².

Hence, only option D is correct, i.e. 64x^2-48x+9 = (8x-3)².

User PussInBoots
by
4.8k points