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3 votes
Solve...........................

Solve...........................-example-1
User Dmitry R
by
5.3k points

1 Answer

6 votes

Answer:

Right option is B. x = -3 ± 2√5

Explanation:

Given equation,

x² + 6x - 11 = 0

Using quadratic formula,


x = \frac{-b ± \sqrt{b^(2) -4ac}}{2a}

Comparing from general quadratic equation: ax² + bx + c = 0

Here, a= 1 b = 6 and c = -11

so,


x = \frac{-6 ± \sqrt{6^(2) -4·1·(-11)}}{2·1}


x = (-6 ± √(36 +44))/(2)


x = (-6 ± √(80))/(2)

x = -3 ± 2√5

Hence right option is B. x = -3 ± 2√5


User Jmettraux
by
5.3k points
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