Question

Solve for x...............

Answer 1

Choice A is correct answer.

Explanation:

Given equation is :

2x²-4x-3=0

ax²+bx+c= 0 is general quadratic equation.

x = (-b±√b²-4ac) / 2a is quadratic formula to find the value of x.

Comparing general quadratic equation with given quadratic equation,we get

a = 2, b= -4 and c = -3

Putting above values in quadratic equation,we get

x = (-(-4±√(-4)²-4(2)(-3)) / 2(2)

x = (4±√16+24) / 4

x = (4±√40) / 4

x = (4±√10×4) / 4

x = (4±2√10) / 4

x = 2(2±√10) / 4

x = (2±√10) / 2

Hence, solution of 2x²-4x-3= 0 is (2±√10) / 2.

Answer 2

Option A

`x=\frac{2(+/-)√(10)} {2}`

Explanation:

we have

`2x^(2)-4x-3=0`

we know that

The formula to solve a quadratic equation of the form
`ax^(2) +bx+c=0` is equal to

`x=\frac{-b(+/-)\sqrt{b^(2)-4ac}} {2a}`

in this problem we have

`2x^(2)-4x-3=0`

so

`a=2\\b=-4\\c=-3`

substitute

`x=\frac{4(+/-)\sqrt{-4^(2)-4(2)(-3)}} {2(2)}`

`x=\frac{4(+/-)√(40)} {4}`

`x=\frac{4(+/-)2√(10)} {4}`

`x=\frac{2(+/-)√(10)} {2}`