Question

a weight hangs from a rope 20 feet long. It swings through an angle of 27 degrees each second. how far does the weight travel each second? round to the nearest 0.1 foot

Answer 1

S=9.42 feet

Explanation:

Since, the length of the rope is 20 feet and it swings through an angle of 27° each second, let s be the distance traveled by the weight, then

using the formula, S=
`\frac{{\theta}}{360^{{\circ}}}{*}2{\pi}r`

Placing the given values, we get

S=
`\frac{27^{{\circ}}}{360^{{\circ}}}{*}2{*}(22)/(7){*}20`

=
`0.075{*}(44)/(7){*}20`

=
`9.42 feet`