Question

Which complex number has a distance of square root of 17 from the origin on the complex plane?

Answer 1

OptionD

Explanation:

4-i option d is the answer

REcall that when z =a+ib for a complex number distance from origin is

modulus z

|z|=
`√(a^2+b^2)`

Apply the above rule for each option

Option 1.

Distance =
`√(2^2+15^2)=√(229)` not our answer

Similarly for option b

Distance = \sqrt{17^2+1^2}=\sqrt{290} not our answer

Option c:

\sqrt{20^2+3^2}=\sqrt{409}not matching with given value

Option d

Distance=\sqrt{4^2+1^2}=\sqrt{17}=given answer

Hence option d is right