Question

Trapezoid ABCD has vertices A(2,4) B(5,4) C(7,1) D(0,1) What is the length of Ad?

Answer 1

The length of AD is
`√(13)\ units`

Explanation:

we know that

the formula to calculate the distance between two points is equal to

`d=\sqrt{(y2-y1)^(2)+(x2-x1)^(2)}`

we have

`A(2,4)\\B(0,1)`

substitute the values

`d=\sqrt{(1-4)^(2)+(0-2)^(2)}`

`d=\sqrt{(-3)^(2)+(-2)^(2)}`

`dAD=√(13)\ units`