106k views
0 votes
one of the solution to this problem below is 8. what is the other solution? C^2-64=0 ( please show your work )

User Masay
by
7.8k points

1 Answer

4 votes

{c}^(2) - 64 = 0
This can also be represented as:

{c}^(2) - {8}^(2) = 0
Using difference of two squares;

(c - 8)(c + 8) = 0

c - 8 = 0 \: or \: c + 8 = 0 \\ \\ c = 8 \: or \: c = - 8



Hope I helped? ☺️
User Ysap
by
8.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories