Question

I am a 3-digit odd number.

The sum of my digits is 9.
My tens digit is twice that if my hundreds digit.
What am I?

Answer 1

Explanation:

let the number at unit place=x

ten's place=y

hundred's place=z

x,y,z are integers.

x+y+z=9

also digit=100z+10y+x

y=2z

x+2z+z=9

x+3z=9

x=1,3,5,7,9

for x=1

1+3z=9

3z=9-1=8

z=8/3 (rejected as z is an integer.)

when x=3

3+3z=9

3z=9-3=6

z=6/3=2

z=2

y=2z=2×2=4

so number=100×2+10×4+3=200+40+3=243

Answer 2

After a long evaluation of counting math, I found that your number is 621.

How and why?

Well, 6 + 2 + 1 = 9, as you already may be aware of. I got this number because it is a three-digit odd number, it sums up to 9, and the tens digit (2) is twice that (or two times the value of) the hundreds digit (1). This one took quite a while, but after listing them, I have prepared my answer and explanation for you! If you need help, let me know and I will gladly assist you.