Question

Solve the following multiplication and division problems.

a. 10 yd. × 3 yd.
b. 15 ft. × 18 ft.
c. 13 yd. 2 ft. 6 in. × 15
d. 198 sq. yd. 8 sq. ft. × 7

Answer 1

Explanation:

a. 10 yd.×3 yd.=30 square yards;

b. 15 ft.×18 ft.=279 square feets;

c. 13 yd.=13×3 ft.=39 ft.=39×12 in.=468 in., 2 ft. 6 in.=2×12+6 in.=30 in., then 13 yd. 2 ft. 6 in.×15=498 in. × 15=7470 in.;

d. 198 sq. yd.=198 ×9 sq. ft.=1782 sq. ft.

198 sq. yd. 8 sq. ft. =1782+8 sq. ft.=1790 sq. ft.

Then 1790 sq. ft. × 7=12530 sq. ft.

Answer 2

To solve these problems, we just need to multiply or divide.

To solve problem c and d, we need to transform all units to the same, and then operate.

a.

`10yd * 3yd = 30yd^(2)`

Remember that
`yd * yd = yd ^(2)`

b.

`15ft * 18 ft = 270 ft^(2)`

c.

`13yd \ 2ft \ 6in * 15`

To solve this one, we need to transform all lengths to yards. We know that 1 yard equals 3 feet and 1 feet equals 12 inches. So,

`(13yd + 2ft(1yd)/(3ft)+6in(1yd)/(36in) * 15\\(13yd+0.67yd+0.17yd) * 15 =207.6yd`

d.

`(198yd^(2) + 8ft^(2)) * 7 \\(198yd^(2) + 8ft^(2)(1yd^(2) )/(9ft^(2) )) * 7 \\(198yd^(2) +0.89yd^(2)) * 7 =1,392.23 yd^(2)`