Answer:
√(cd)*∛d
Explanation:
This problem becomes a bit easier if we group the variables c and d together.
(cd)^(1/2)*d*(1/3) = c^(1/2)*d^(1/2+1/3)
Continuing, we get c^(1/2)*d^(5/6) (by adding the exponents 1/2 and 1/3)
Now c^(1/2) is equivalent to the radical form √c, and
d^(5/6) is equivalent to d^(5/3)^(1/2), which, as a radical, is √d(5/3).
Summarizing this:
(cd)^(1/2)*d*(1/3) = c^(1/2)*d^(1/2+1/3) = (cd)^(1/2)*d^(1/3),
which, in radical form, is √(cd)*∛d