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PLEASE HELP ASAP!!!

What is the midpoint of AC?

A. (4a, 4b)
B. (2a, 2b)
C. (a, b)
D. (a/2, b/2)

PLEASE HELP ASAP!!! What is the midpoint of AC? A. (4a, 4b) B. (2a, 2b) C. (a, b) D-example-1
User La Masse
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2 Answers

2 votes

Answer:

Choice C is correct.

Explanation:

The formula to find mid-point of a line segment is:

M= (
x_(1)+x_(2)/2,
y_(1) +y_(2)/2)

where (
x_(1) ,y_(1)) and (
x_(2) ,y_(2)) are end-points of a line segment.

we have to find mid-point of AC.

A is located at the center of xy-graph.

hence, A(
x_(1) ,y_(1)) is given as (0,0) and C(
x_(2) ,y_(2)) is given as (2a,2b).

put above values in the formula of mid-point formula:

M=(0+2a/2,0+2b)

M=(2a/2,2b/2)

M=(a,b) is mid-point of AC.




User Asynts
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4.9k points
5 votes

Answer:

C. (a, b)

Explanation:

The formula of a midpoint:


M\left((x_1+x_2)/(2);\ (y_1+y_2)/(2)\right)

We have A(0, 0) and C(2a, 2b). Substitute:


x=(0+2a)/(2)=(2a)/(2)=a\\\\y=(2b+0)/(2)=(2b)/(2)=b

M(a, b)

User Desval
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5.3k points