Question

PLease help ASAP!

Write each ratio:


sin A:
cos A:
tan A:
sin B:
cos B:
tan B:

Answer 1

`sine=(opposite)/(hypotenuse)\\\\cosine=(adjacent)/(hypotenuse)\\\\tangent=(opposite)/(adjacent)\\-----------------------\\\\hypotenuse=AB=10\\\\for\ \angle A:\\opposite=CB=8\\adjacent=AC=6\\\\for\ \angle B:\\opposite=AC=6\\adjacent=CB=8\\----------------------------`

`\text{Substitute:}\\\\\sin A=(8)/(10)=(8:2)/(10:2)=(4)/(5)\\\\\cos A=(6)/(10)=(6:2)/(10:2)=(3)/(5)\\\\\tan A=(8)/(6)=(8:2)/(6:2)=(4)/(3)\\\\\sin B=(6)/(10)=(6:2)/(10:2)=(3)/(5)\\\\\cos B=(8)/(10)=(8:2)/(10:2)=(4)/(5)\\\\\tan B=(6)/(8)=(6:2)/(8:2)=(3)/(4)`

`\text{Conclusion:}\\\\\sin A=\cos B\ and\ \cos A=\sin B\ and\ \tan A=(1)/(\tan B)`