Answer:
The graph touches the x-axis at x=0 and crosses the x-axis at x=5 and x=-2.
Explanation:
We have the following function and we are to solve it for x:
![f(x)=-x^4+3x^3+10x^2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/cefxbr1hvmn6oh1gc697v9zyapuk3bktr6.png)
We will put the given function equal to zero and solve it as we know that the function crosses the x-axis when y = 0.
![-x^4+3x^3+10x^2=0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/jjk7glv597jyi7i87qntmjvy1iwh5sdcs6.png)
So taking the common terms out:
![-x^2(x^2-3x-10)=0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/d8t2qb9l03wu40yqayfagneuetel6k445l.png)
![-x^(2) (x-5)(x+2)=0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/97u0asgvhoau42mfpzgig7bdvmbc8li9gj.png)
![-x^(2) =0, x=0](https://img.qammunity.org/2020/formulas/mathematics/middle-school/hmj92cxnuq1h4v0vx26yz4xq3t0k8m3pgc.png)
![(x-5)=0, x=5](https://img.qammunity.org/2020/formulas/mathematics/middle-school/o72p4twz34wmk1j00ru3d689f9ho4bqlb8.png)
![(x+2)=0, x=-2](https://img.qammunity.org/2020/formulas/mathematics/middle-school/1m1wx54gv946o402akeebo4xnbxlgj79oi.png)
Therefore, the graph touches the x-axis at x=0 and crosses the x-axis at x=5 and x=-2.