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1 vote
What is the product of (3p-7)(2p²-3p-4)

A.6p³+23p²+9p+28
B.6p³-23p²-9p+28
C.6p³-23p²+9p+28
D.6p³+23p²-9p+28

User STLMikey
by
8.1k points

1 Answer

4 votes

Answer:

Choice C is the correct answer.

Explanation:

Given expression is

(3p-7)(2p²-3p-4)

we have to find the product of linear expression to quardatic expression.

Firstly, multiply 3p to quardatic expression and -7 to quardatic expression and add.

3p(2p²-3p-4)-7(2p²-3p-4)

Multiply 3p to each term of quardatic expression and -7 to each term of quardatic expression and add all terms:

3p(2p²)+3p(-3p)+3p(-4)-7(2p²)-7(-3p)-7(-4)

6p³-9p²-12p-14p²+21p+28

add like terms

6p³+(-9-14)p²+p(-12+21)+28

6p³-23p²+9p+28 which is the correct answer.


User Troskyvs
by
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