The final velocity of the skateboarder is 23.75 m/s.
We can use conservation of momentum to calculate the magnitude of the final velocity.
Momentum before collision is equal to the momentum after collision
m1v1+m2v2=(m1+m2)v
here, v is final velocity of the skateboarder, assuming right side velocity as positive, and left side velocity as negative.
70*12+2000*(-25)=(70+2000)v
v=-23.75 m/s
Here, negative sign indicates that both skyboarder and bus will move in left direction.