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W(x)=5^x odd or even

User Andersvold
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2 Answers

5 votes

Answer:

See below

Explanation:

w(x) = 5^x

For x = positive integer 5^x will always have 5 as the last digit so it will always be Odd.

For x = 0, 5^x = 1 (odd).

User Shamnad P S
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8.2k points
4 votes

Answer:

w(x) is neither even nor odd.

Explanation:

w(x) = 5^x is an exponential function defined for all real numbers.

The test for "evenness" is to choose an input value (x-value), such as 3, evaluate the function (result: 125), reflect the graph about the y-axis, and then determine whether the negative of the input value produces the same output.

It does not. Whereas w(3) = 125, w(-3) = 1/125. Since these results differ, we know definitively that this function is not even.

The test for "oddness" is somewhat similar in that we choose an input value such as 3 and then evaluate the function w(x) at both 3 and -3. If

w(-3) = - w(3), then the function is odd. That's not the case here. We know definitively that w(x) is not odd.

It's neither even nor odd.

User Romain Linsolas
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