Question

32p and 31p are two isotopes of phosphorus. Compare the number if subatomic particles that are present in the atoms of these isotopes.

Answer 1

Answer: Thus for
`_(15)^(32)\textrm{P}` , no of electrons = no of protons = 15, number of neutrons = 17

For
`_(15)^(31)\textrm{P}` , no of electrons = no of protons = 15, number of neutrons = 16.

Step-by-step explanation:

Isotopes are elements which have same atomic number but different mass number.

General representation of an element is given as:
`_Z^A\textrm{X}`

where,

Z represents Atomic number

A represents Mass number

X represents the symbol of an element

Thus the isotopes of phosphorous are represented as
`_(15)^(32)\textrm{P}` and
`_(15)^(31)\textrm{P}`

An atom is smallest unit of a matter or substance.It consist of three subatomic particles : electrons, protons, neutrons.

Mass number is defined as the sum of number of protons and neutrons that are present in an atom.

Mass number = Number of protons + Number of neutrons

Atomic number is defined as the number of protons or number of electrons that are present in an atom.

Atomic number = Number of electrons = Number of protons

Thus for
`_(15)^(32)\textrm{P}` , no of electrons = no of protons = 15 and number of neutrons = 32-15= 17.

Thus for
`_(15)^(31)\textrm{P}` , no of electrons = no of protons = 15 and number of neutrons = 31-15= 16.

Answer 2

Answer & Explanation:

Subatomic particles are particles much smaller than atoms.

Atoms are composed mainly of protons, neutrons, and electrons.

³²P:

• number of electrons: 15,

• number of protons: 15,

• number of neutrons: 17.

³¹P:

• number of electrons: 15,

• number of protons: 15,

• number of neutrons: 16.