Question

Why is there also a 2 outside of the radical symbol? Is it because there’s one pair of 2’s?

Answer 1

Answer: It's because a triple of threes was moved outside of the radical.

Explanation:

`\sqrt[3]{4*5*2*5*7} = \\\sqrt[3]{2*2*5*2*5*7} = \\\sqrt[3]{2*2*2*5*5*7} = \\\sqrt[3]{2*2*2}\sqrt[3]{5*5*7} = \\2\sqrt[3]{5*5*7}`

Answer 2

I would say that stands for "2 times the cube root of (5) * (5) * (7)"

Explanation: