Hello from MrBillDoesMath!
Answer:
2x + h
Discussion:
This quotient commonly appears in the study of differential Calculus.
For f(x) = x^ 2:
( f(x+h) - f(x) ) /h =
( (x +h)^2 - x^2) ) /h =
( (x^2 + 2xh + h^2) - x^2) / h = => as x^2 - x^2 = 0
( 2xh + h^2 ) /h = => divide by "h"
2x + h
Thank you,
MrB