Question

An elevator is initially moving upward at a speed of 12.60 m/s. The elevator experiences a constant downward acceleration of magnitude 3.60 m/s2 for 2.97 s.

Answer 1

I'm assuming you're asking for the elevator's final velocity.

Consider the following equation:

Vf = Vi + aΔt

Vf is the final velocity.

Vi is the initial velocity.

a is the acceleration.

Δt is the amount of elapsed time.

Given values:

Vi = 12.60m/s

a = -3.60m/s²

Δt = 2.97s

Substitute the terms in the equation with the given values and solve for Vf:

Vf = 12.60 - 3.60×2.97

Vf = 1.91m/s