Question

Hw 43 special right triangles

Answer 1

Part 8)
`v=8√(3)\ units` and
`u=16\ units`

Partt 9)
`x=5√(3)\ units` and
`y=5\ units`

Part 10)
`x=8√(3)\ units` and
`y=4√(3)\ units`

Part 11)
`a=22\ units` and
`b=11\ units`

Explanation:

Part 8) we know that

Find the value of v

`tan(60\°)=(v)/(8)`

solve for v

`v=8*tan(60\°)=8√(3)\ units`

Find the value of u

`cos(60\°)=(8)/(u)`

solve for u

`u=(8)/(cos(60\°))=(8)/((1/2))=16\ units`

Part 9) we know that

Find the value of y

`cos(60\°)=(y)/(10)`

solve for y

`y=10*cos(60\°)=5\ units`

Find the value of x

`tan(60\°)=(x)/(5)`

solve for x

`x=5*tan(60\°)=5√(3)\ units`

Part 10) we know that

Find the value of y

`tan(30\°)=(y)/(12)`

solve for y

`y=12*tan(30\°)=4√(3)\ units`

Find the value of x

`cos(30\°)=(12)/(x)`

solve for x

`x=(12)/(cos(30\°))=8√(3)\\ units`

Part 11) we know that

Find the value of a

`cos(30\°)=(11√(3))/(a)`

solve for a

`a=(11√(3))/(cos(30\°))=22\ units`

Find the value of b

`sin(30\°)=(b)/(22)`

solve for b

`b=22*sin(30\°)=11\ units`