Question

What are the first six terms of the sequence a1=0,an=an-1-8

Answer 1

a1 =0

a2 = -8

a3 = -16

a4 = -24

a5 = -32

a6 = -40

Explanation:

a1 =0

an = an-1 -8

We subtract 8 each time

a1 =0

a2 = 0-8 = -8

a3 = -8 -8 = -16

a4 = -16 -8 = -24

a5 = -24-8 = -32

a6 = -32-8 = -40

Answer 2

0, -8, -16, -24, -32, -40

Explanation:

`a_1=0\\\\a_n=a_(n-1)-8\\\\\text{Put n = 2, n = 3, n = 4, n = 5 and n = 6 to the expression:}\\\\a_2=a_1-8\to a_2=0-8=-8\\\\a_3=a_2-8\to a_3=-8-8=-16\\\\a_4=a_3-8\to a_4=-16-8=-24\\\\a_5=a_4-8\to a_5=-24-8=-32\\\\a_6=a_5-8\to a_6=-32-8=-40`