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an object is projected upward with an initial velocity of 124 ft per? sec, its height h after t seconds is h equals negative 16 t squared plus 124 t. Find the height of the object after 5 seconds.

1 Answer

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Answer:

220 ft

Explanation:

h = -16t^2 +124t

Let t=5

h = -16(5)^2 +124(5)

= -16(25) +124(5)

=-400+620

= 220

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