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The average test scores for a particular test in algebra was 84 with a standard deviation of 5. What percentage of the students scored higher than 89%? Please explin your answer.

User Aacanakin
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1 Answer

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Answer:

The percentage of the students scored higher than 89% is 15.87%

Explanation:

we are given

The average test scores for a particular test in algebra was 84

so, mean is 84


\mu=84

a standard deviation of 5

so,


\sigma=5

we have

x=89

now, we can use z-score formula


z=(x-\mu)/(\sigma)

now, we can plug values


z=(89-84)/(5)


z=1

now, we can use calculator

and we get


p(z>1)=0.1587

So,

The percentage of the students scored higher than 89% is 15.87%

User Felipe Francisco
by
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