Answer:
![2300 + 0.08x \geq 2700](https://img.qammunity.org/2020/formulas/mathematics/high-school/syix361abc7vrmrlgrmrwl0y0armtuzrih.png)
and
![x\geq 5000](https://img.qammunity.org/2020/formulas/mathematics/high-school/v3bi4m7o08r8ofx8flroqp2yg8uu2msoye.png)
Explanation:
Liz earns $2300. She then earns in addition to this 8% or 0.08 of what she sells. This is 0.08x. Together she earns 0.08x + 2300. If she wants to earn at least 2700 then this expression must be greater than or equal to 2700.
Combine these to write
.
Solve:
![2300 + 0.08x \geq 2700\\\\2300-2300+0.08x\geq 2700-2300\\\\0.08x\geq 400\\\\x\geq 5000](https://img.qammunity.org/2020/formulas/mathematics/high-school/nmxy5ymify4kjm1f9wb9aimi893qtuxdmk.png)