Question

ChevyChaseisslidingdownahillinatobogganatarateof5m/swhenhereaches and even steeper slope. If he accelerates at 2 m/s2 for the 5 m slope, how fast is he traveling when he reaches the bottom of the 5 m slope?

Answer 1

Answer : v = 6.7 m/s

Explanation :

It is given that :

Initial velocity, u = 5 m/s

Acceleration,
`a=2\ m/s^2`

Distance, s = 5 m

Using equation of motion:

`v^2-u^2 =2as`

`v^2-(5\ m/s)^2=2* 2\ m/s^2* 5\ m`

`v^2=45\ m/s`

`v=6.7\ m/s`

So, when he reaches the bottom of 5 m slope he is travelling with travelling with 6.7 m/s.