Question

Use the quadratic formula to solve the equation. If necessary, round to the nearest hundredth 5y^2-8y=2

Answer 1

Explanation:

First, rewrite the equation (all terms should be in the left side):

`5y^2-8y-2=0.`

In this equation,

• 
  `a=5;`
• 
  `b=-8;`
• 
  `c=-2.`

Then the discriminant

`D=b^2 -4ac=(-8)^2-4\cdot 5\cdot (-2)=64+40=104.`

Then

`y_1=(-b+√(D))/(2a)=(-(-8)+√(104))/(2\cdot 5)=(8+2√(26))/(10)=(4+√(26))/(5),\\ \\y_2=(-b-√(D))/(2a)=(-(-8)-√(104))/(2\cdot 5)=(8-2√(26))/(10)=(4-√(26))/(5).`