Question

A 70 kg person standing in an elevator is accelerated upwards at a rate of 2.5 m/s2. What is the force of the elevator on the person?

770 N
250 N
875 N
-525 N

Answer 1

Your answer will be
875N

Answer 2

F' = 875 N

Step-by-step explanation:

It is given that,

Mass of the person, m = 70 kg

Acceleration of the elevator,
`a=2.5\ m/s^2` (accelerating upward)

We need to find the force of the elevator on the person. When the elevator is moving upward the force acting on it is given by :

`F'=ma+mg`

g is the acceleration due to gravity

`F'=m(a+g)`

`F'=70* (2.5+10)`

F' = 875 N

So, the force of the elevator on the person is 875 N. Hence, this is the required solution.