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Which of the following is a area of the special trepezoid if ab=19,cd=19 and the height is 14

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As, Opposite side of Special trapezoid is equal.So, it will be a Parallelogram.

ab=c d= 19 units

Height of Trapezoid = 14 units

Area of Trapezoid =
(1)/(2) * {\text{Sum of parallel sides}} * {\text{Perpendicular Distance between them}}


=(1)/(2)* (19+19) * 14\\\\ =(1)/(2) * 38 * 14\\\\ = 19 * 14\\\\= 266

So, Area of Trapezoid = 266 square units

You, can use the formula for finding the area of parallelogram,which is = Base on which perpendicular is drawn × Length of Altitude

= 19 × 14

= 266 square units

Which of the following is a area of the special trepezoid if ab=19,cd=19 and the height-example-1
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