Question

1.What is the specific heat capacity of granite when 20 kg absorbs 237 000 J of heat energy, causing its temperature to increase by 15 °C? (you are finding c)​

Answer 1

Given :

• Amount = 20 kg
• Heat energy absorbed = 237,000 J
• Temperature change = 15 °C

Formula applied :

`\boxed {Q = mc \triangle T}`

• Q = absorbed heat
• m = mass
• c = specific heat capacity
• ΔT = temperature change

Let's solve for c !

⇒ 237,000 = 20 × c × 15

⇒ c = 237,000 ÷ 300

⇒
`\boxed {c = 790 J kg^(-1) K^(-1)}`

∴ The specific heat capacity of granite is 790 J kg⁻¹ K⁻¹.