Find a polynomial function of degree 5 with -3 as a zero of multiplicity 3, 0 as a zero of multiplicity 1, and 3 as a zero of multiplicity 1.

asked Feb 6, 2023 64.5k views

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10 votes

$(x+3)^3\cdot x\cdot (x-3)=(x^3+9x^2+27x+27)\cdot (x^2-3x)=\\=x^5-3x^4+9x^4-27x^3+27x^3-81x^2+27x^2-81x=\\=x^5+6x^4-54x^2-81x$

Daram answered Feb 11, 2023

by Daram

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