Question

At the end of a recent WNBA regular season, the Phoenix murmur had 12 more victories than losses. The number of victories they had was one more than two times the number of losses. How many regular season games did the Phoenix Mercury play during that season?

Answer 1

To solve this problem, set up a system of equations using 'v' as the number of victories and 'l' as the number of losses. Substitute the first equation into the second equation, simplify and solve for 'l'. Substitute the value of 'l' back into the first equation to find the total number of games.

Step-by-step explanation:

To solve this problem, we can set up a system of equations. Let's use the variable 'v' to represent the number of victories and 'l' to represent the number of losses. We are given two pieces of information:

1. At the end of the season, the Phoenix Mercury had 12 more victories than losses: v = l + 12.

2. The number of victories they had was one more than two times the number of losses: v = 2l + 1.

We can solve this system by substituting the first equation into the second equation:

1. Substitute v = l + 12 into the second equation: l + 12 = 2l + 1.
2. Combine like terms: 12 - 1 = 2l - l. Simplify this to: 11 = l.
3. Substitute l = 11 back into the first equation to solve for v: v = 11 + 12 = 23.

Therefore, the Phoenix Mercury played a total of 23 regular season games during that season.

Answer 2

34 games

Step-by-step explanation:

let the number of losses be
`l`

let the number of victories be
`v`

the Phoenix murmur had 12 more victories than losses:

`v=l+12`

The number of victories they had was one more than two times the number of losses:

`v=2l+1`

We have 2 expressions for
`v`, equating these 2, we can solve for
`l`:

`l+12=2l+1\\12-1=2l-l\\11=l`

So 11 games, they lost.

Using this value, we can plug into the 1st equation to solve for v:

`v=l+12\\v=11+12\\v=23`

So 23 games, they won.

Given that no draws, they played a total of 23 + 11 = 34 games this season