Question

what is the equation, in slope-intercept from, of the line that is perpendicular to the line y - 4 = -2/3 (x -6 ) and passes through the point (-2,-2)?

Answer 1

Turn y - 4 = -2/3(x - 6) into a linear equation.

y - 4 = -2/3(x - 6)

y - 4 = -2/3x + 4

+4 +4

y = -2/3x + 8

The equation that is perpendicular to y = -2/3x + 8 is y = 3x + 4 as shown in the image below using a graph.