Question

NEED HELP ASAP 70 POINTS

Given: ​​ ​ △ACE,BD¯¯¯¯¯∥AE¯¯¯¯¯ ​

Prove: BA/CB=DE/CD

Drag an expression or phrase to each box to complete the proof.

Answer 1

Ayo, for anyone who needs it -

Answer 2

Explanation:

Statement Reason

ΔACE, BD║AE Given

∠4≅∠1 and ∠3≅∠2 Corresponding angle postulate

ΔACE is similar to ΔBCD Angle-Angle similarity postulate

`(CA)/(CB)=(CE)/(CD)` Definition of similar triangles

CA=CB+BA and CE=CD+DE Segment addition postulate

`(CB+BA)/(CB)=(CD+DE)/(CD)` Substitution property of equality.

`(CB)/(CB)+(BA)/(CB)=(CD)/(CD)+(DE)/(CD)` Addition of fractions.

`1+(BA)/(CB)=1+(DE)/(CD)` Simplification of fractions

`(BA)/(CB)=(DE)/(CD)` Subtraction property of equality.