Question

A force of 6600 N is exerted on a piston that has an area of 0.010
`m^(2)`. What area is rewired for a second piston to exert a force of 9900 N? Use
`(F_(1) )/(A_(1) ) = (F_(2) )/(A_(2) )`

A. 0.0015
`m^(2)`

B. 66
`m^(2)`

C. 150
`m^(2)`

D. 0.006
`m^(2)`

Answer 1

Correct answer is
`.015m^2` which is not any option

Solution

In this question we have given,

force on piston 1,
`F_(1)`=6600N

Area of piston 1,
`A_(1)`=
`.010m^2`

Force on piston 2,
`F_(2)`=9900N

we have to find area of piston 2,
`A_(2)`=?

According to Pascal's law, the pressure is transmitted with equal intensity to every part of the fluid:

It means,

`p_(1)= p_(2)`

which becomes

`(F_(1) )/(A_(1)) =(F_(2) )/(A_(2))`

`A_(2)=(A_(1)* F_(2))/(F_(1) )`.........(1)

Put values of
`A_(1),F_(1) and F_(2)` in equation 1

`A_(2)=(.010m^2* 9900N)/(6600N)`

`A_(2)=0.015m^2`