101k views
3 votes
Find the zero of the given polynomial :

p(x) = {x}^(2) + 1

2 Answers

6 votes

Answer:

+i , -i

Step-by-step explanation:

Zero of the polynomial:

p(x) =0

x² + 1 = 0

x² = -1

Take square root both sides,


\sf x = √(-1)\\\\x =√(i^2)\\

x = ± i

Zeros of the polynomial:

x = +i , -i

User CLNRMN
by
6.1k points
8 votes

Answer:

x = i, -i

Step-by-step explanation:

p(x) = x² + 1

To set a polynomial to zero, p(x) = 0.

⇒ x² + 1 = 0

relocate variable

⇒ x² = -1

square root both sides

⇒ x = ±√-1

breakdown

⇒ x = √-1, -√-1

simplify if x = √-a then √a i

⇒ x = i, -i

User Kamil Harasimowicz
by
6.1k points
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