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When multiplying 2x-8/x^2-4 times x^2+6x+8/x-4, what are the term(s) that can be cancelled

User Sofire
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1 Answer

4 votes

Answer:

(x-4) and (x+2) are terms that can be cancelled

Explanation:

we are given


(2x-8)/(x^2-4)* (x^2+6x+8)/(x-4)

Firstly, we will factor terms

and then we can cancel common terms


2x-8=2(x-4)


x^2-4=(x-2)(x+2)


x^2+6x+8=(x+4)(x+2)

now, we can replace it


(2x-8)/(x^2-4)* (x^2+6x+8)/(x-4)=(2(x-4))/((x-2)(x+2))* ((x+2)(x+4))/(x-4)

now, we can see that

(x-4) and (x+2) are common

so, they will get cancelled


(2x-8)/(x^2-4)* (x^2+6x+8)/(x-4)=(2)/((x-2))* ((x+4))/(1)

so, we can see that

(x-4) and (x+2) are terms that can be cancelled

User Nicholas Allio
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7.8k points

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